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Oct 22nd, 2018
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  1. int __cdecl sub_5C2080(int a1)
  2. {
  3. int result; // eax@3
  4. int v2; // ST04_4@3
  5.  
  6. if ( *(*(a1 + 16) + 68) >= *(*(a1 + 16) + 64) )
  7. sub_5C7560(a1);
  8. result = sub_5C6900(a1);
  9. v2 = *(a1 + 8);
  10. *v2 = result;
  11. *(v2 + 4) = 8;
  12. *(a1 + 8) += 8;
  13. return result;
  14. }
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