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- #include <iostream>
- #include <math.h>
- using namespace std;
- void write(unsigned int n, int tab1[], int tab2[]){
- for(int i = 0; i < n; i++){
- tab2[i] = tab1[i];
- }
- }
- void rewrite(unsigned int n, int tab1[], int tab2[]){
- int x = 0;
- while(n > 0){
- n--;
- tab2[n] = tab1[x];
- x++;
- }
- }
- int main() {
- int tab1[5];
- tab1[0] = 0;
- tab1[1] = 1;
- tab1[2] = 2;
- tab1[3] = 3;
- tab1[4] = 4;
- int tab2[5];
- tab2[0] = 5;
- tab2[1] = 6;
- tab2[2] = 7;
- tab2[3] = 8;
- tab2[4] = 9;
- cout << "Wartosci tab1: " << endl;
- for(int i = 0; i < 5; i++){
- cout << tab1[i] << endl;
- }
- cout << "Wartosci tab2: " << endl;
- for(int i = 0; i < 5; i++){
- cout << tab2[i] << endl;
- }
- write(5, tab1, tab2);
- cout << "Wartosci tab1: " << endl;
- for(int i = 0; i < 5; i++){
- cout << tab1[i] << endl;
- }
- cout << "Wartosci tab2: " << endl;
- for(int i = 0; i < 5; i++){
- cout << tab2[i] << endl;
- }
- //PODPUNKT B
- tab1[0] = 0;
- tab1[1] = 1;
- tab1[2] = 2;
- tab1[3] = 3;
- tab1[4] = 4;
- tab2[0] = 5;
- tab2[1] = 6;
- tab2[2] = 7;
- tab2[3] = 8;
- tab2[4] = 9;
- cout << "PODPUNKT B" << endl;
- cout << "Wartosci tab1: " << endl;
- for(int i = 0; i < 5; i++){
- cout << tab1[i] << endl;
- }
- cout << "Wartosci tab2: " << endl;
- for(int i = 0; i < 5; i++){
- cout << tab2[i] << endl;
- }
- rewrite(5, tab1, tab2);
- cout << "Wartosci tab1: " << endl;
- for(int i = 0; i < 5; i++){
- cout << tab1[i] << endl;
- }
- cout << "Wartosci tab2: " << endl;
- for(int i = 0; i < 5; i++){
- cout << tab2[i] << endl;
- }
- return 0;
- }
- /*
- zad 2
- napisz funkcje ktora otrzymuje 3 argumenty dodatnia liczbe int n oraz dwie n elementowe tablice tab 1
- tab 2 o elementach typu int i;
- a) przepisuje zawartosc tablicy tab1 do tablicy tab2
- b) przepisuje zawartosc tablicy tab 1 o tablicy tab 2 w odwrotnej kolejnosci czyli element tab1[0] ma zostac zapisany do komorki tablicy tab2 o indeksie n-1
- */
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