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May 21st, 2018
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  1. int word(char *s, char *t, char *pt)
  2. {
  3. int i=0,ind=0,len=0;
  4. for(i=0;s[i];i++)
  5. {
  6. if(strchr(t,s[i])==NULL && s[i]!=';')
  7. {
  8. if(len==0)
  9. ind=i;
  10. len++;
  11. }
  12. if(len!=0 && (strchr(t,s[i]) || (s[i]==';') || !s[i+1]))
  13. {
  14. strncpy(pt,s+ind,len);
  15. pt[len]=0;
  16. break;
  17. }
  18. }
  19. //printf("3)len of the word: %d\n",len);
  20. return len;
  21. }
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