Examen de bacalaureat 2020 - Variante propuse - Varianta 2 (Matematica Informatica - Olimpici)

I.
1.a.
2.d.
3.a
4.b
5.c

II.
1.a. 2020
  b. 1234 2345
  c.
#include <iostream>

using namespace std;

int main()
{ int n,m,i,x;
cin>>n;
m=0;
for(int i=1;i<=n;i++)
{
    cin>>x;
    while(x%10>(x/10)%10) x=x/10;
    m=m+x;
}
if(m>0) cout<<m;
  else cout<<"niciunul";
    return 0;
}

  d.
citește n (număr natural nenul)
 m=0
 i=1;
┌cat timp (i<=n)
│ citește x (număr natural)
│┌cât timp x%10 > [x/10]%10 execută
││ x=[x/10]
│└■
│ m=m+x
│ i++;
└■
┌dacă m>0 atunci scrie m
│altfel scrie „niciunul”
└■


2.
struct figura{ struct {float x,y;}centru;
               float raza;
               }c;

3.
for(i=0;i<7;i++)
for(j=0;j<=j<7;j++)
if(i>j)
a[i][j]="+";
else
if(i==0)
a[i][j]=char("a"+j);
else
a[i][j]=a[i-1][j-1];

III.
1.
int multiplu(int n)
{int ok=0,i=1,cn;
while(ok==0)
{cn=n*i;
if(sqrt(cn)*sqrt(cn)==cn)
return cn;
i++;
}
}

2.
#include <bits/stdc++.h>
using namespace std;
int main()
{char s[101];
int i,n,ok=0;
cin.getline(s,101);
n=strlen(s)+1;
for(i=0;i<n;i++)
{if(s[i]=='<')
ok=1;
if(s[i]=='>')
ok=0;
if(ok==1 && s[i]>='a' && s[i]<='z')
s[i]=char(s[i]-('a'-'A'));}
cout<<s;
    return 0;
}


3.
#include <bits/stdc++.h>
using namespace std;
ifstream fin("bac.in");
int main()
{int d,a,aa,c,mini=2e9,cc=0,ok=0;
fin>>aa>>a;
while(fin>>c)
{if(a>aa && a>c)
    {ok=1;
        d=abs(aa-c);
if(d<mini)
    {cc=a;
    mini=d;}
else
if(d==mini)
    cc=max(cc,a);}
aa=a;
a=c;
}
if(ok==1)
cout<<cc;
else
cout<<"NU EXISTA";
    return 0;
}