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Mar 24th, 2018
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  1. date v1 v2
  2. 1991 1 2
  3. 1991 1 3
  4. 1991 2 1
  5. 1991 2 3
  6. 1992 1 1
  7.  
  8. etc
  9.  
  10. aggregate(df$v2, by = list(df$date), mean)
  11.  
  12. date v1 v2
  13. 1991 1 2,5
  14. 1991 2 2
  15. 1992 1 1
  16. etc
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