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a guest Apr 23rd, 2019 68 Never
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  1. #include<bits/stdc++.h>
  2. using namespace std;
  3. double a[20][20],d,det;
  4. int n;
  5. int prim(int a) {
  6.     if(a < 2)
  7.         return 0;
  8.     for(int i = 2; i * i <= a; i++)
  9.         if(a % i == 0)
  10.             return 0;
  11.     return 1;
  12.     }
  13.  
  14. int prime = 0;
  15. int main(){
  16.     ifstream cin("prob.in");
  17.     ofstream cout ("prob.out");
  18.     cin>>n;
  19.     for(int i=1;i<=n;i++)
  20.         for(int j=1;j<=n;j++)
  21.             cin>>a[i][j];
  22.     for(int i=1;i<=n;i++){
  23.         for(int j=i+1;j<=n;j++)
  24.             if(j!=i){
  25.                 d=a[j][i]/a[i][i];
  26.                 for(int k=1;k<=n;k++)
  27.                     a[j][k]-=a[i][k]*d;
  28.             }
  29.     }
  30.     cout<<endl<<"matricea zerografiata "<<endl;
  31.     for(int i=1;i<=n;i++){
  32.         for(int j=1;j<=n;j++)
  33.             cout<<setprecision(2)<<fixed<<a[i][j]<<' ';
  34.         cout<<endl;
  35.     }det=1;
  36.     for(int i=1;i<=n;i++){
  37.         det*=a[i][i];
  38.         if(prim(abs(a[i][i]))){
  39.             prime++;
  40.         }
  41.         }
  42.     cout<<"Determinantul ="<<det<<endl;
  43.     if(prime > 1)cout << "avem "<<prime << " nr prime pe diagonala" <<endl;
  44.     if(prime = 1)cout << "avem un numar prim pe diagonala"<<endl;
  45.     if(!prime) cout << "nu sunt numere prime pe diagonala " <<endl;
  46.     return 0;
  47. }
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