Not a member of Pastebin yet?
Sign Up,
it unlocks many cool features!
- #!/bin/bash
- echo "请您输入你想删除的文件个数(时间越早的文件靠前):"
- read file_num
- total_file_num=`ls -l | grep "^d" | wc -l` # 统计目录文件的个数
- if (( $file_num > $total_file_num ))
- then echo "您要删除的文件数目太多!"
- else
- ls -ltr | grep -v 'total' | grep "^d" | awk '{print $9}' | head -n $file_num | xargs rm -rf
- echo "删除成功!"
- fi
- # grep -v 'total' :去除ls中显示“total”的行
Add Comment
Please, Sign In to add comment