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Oct 20th, 2018
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  1. for (int i = 1; i <= n; i++)
  2. for (int j = 1; j <= m; j++)
  3. a[i][j] = (i + j)%2, k[(i + j)%2][i]++;
  4. int b = 0, w = 0;
  5. for (int i = 1; i <= n; i++)
  6. b += k[1][i];
  7. vector<int> x;
  8. for (int i = 0; i <= n; i++){
  9. b -= k[1][i];
  10. w += k[0][i];
  11. x.pb(b + w);
  12. }
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