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- #include <iostream>
- #include <iomanip>
- #include<cmath>
- using namespace std;
- int main()
- {
- double cenanaekskurzia;
- cin >> cenanaekskurzia;
- int broipazeli, broigovoreshtikukli, broiplushenimecheta, broiminioni, broikamioncheta;
- cin >> broipazeli >> broigovoreshtikukli >> broiplushenimecheta >> broiminioni >> broikamioncheta;
- double suma = broipazeli*2.60 + broigovoreshtikukli * 3 + broiplushenimecheta*4.10 + broiminioni*8.20 + broikamioncheta * 2;
- double broiigrachki = broipazeli + broigovoreshtikukli + broiplushenimecheta + broiminioni + broikamioncheta;
- //double otstapka = 0.25*suma; - ne se izchislqva tuk
- double pechalba = 0.00;
- //double krainacena = suma - otstapka; - izlischno
- //double naem = 0.10*krainacena; - ne mu e nqstoto tuk
- //double pechalba = krainacena - naem; ne mu e mqstoto tuk
- //double ostavashtipari = pechalba - cenanaekskurzia; - ne mu e mqstoto tuk
- //double nedostig = cenanaekskurzia - pechalba; - ne mu e mqstoto tuk
- if (broiigrachki >= 50)
- {
- // tuk izchislqvame otstapkata ako igrachkite sa >= 50 br.
- pechalba = suma - suma * 25.0 / 100; // tova e otstapkata
- pechalba = pechalba - (pechalba * 10) / 100; // tova e naema sled nachislenata otstapka
- }
- else
- {
- // ako igrachkite sa po-malko ot 50 togava nachislqvame samo naema
- pechalba = suma - (suma * 10.0 / 100);
- }
- double ostavashtipari = abs(pechalba - cenanaekskurzia); // s pomoschta na abs() vzimame absoliutnata stojnost na izraza i taka go otpechatvame ne kato otricatelno chislo ako parite ne dostigat
- if (pechalba >= cenanaekskurzia)
- {
- // ako pechalbata e dostatachna za ekskurziata
- cout << fixed << setprecision(2) << "Yes!" << " " << ostavashtipari << " lv left." << endl;
- }
- else
- {
- // ako pechalbata ne e dostatachna za ekskurziata
- pechalba *= 0.75;
- cout << fixed << setprecision(2) << "Not enough money!" << " " << ostavashtipari << " lv needed." << endl;
- }
- return 0;
- }
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