Untitled

Hi experts, I believe this tricky task might be interesting FOR you.
WITH settings AS (
SELECT 'key1' AS KEY, 'include' AS what_to_do UNION ALL
SELECT 'key2' AS KEY, 'include' AS what_to_do UNION ALL
SELECT 'key3' AS KEY, 'exclude' AS what_to_do
),
DATA AS (
SELECT 'value_with_key1_and_other_stuff' AS string_with_data UNION ALL
SELECT 'value_with_key2_and_other_stuff' AS string_with_data UNION ALL
SELECT 'value_with_key3_and_other_stuff' AS string_with_data UNION ALL
SELECT 'value_with_key4_and_other_stuff' AS string_with_data UNION ALL
SELECT 'value_with_key1_key3_and_other_stuff' AS string_with_data UNION ALL
SELECT 'just_a_test' AS string_with_data
)
SELECT * FROM DATA
I got two TABLES, DATA AND settings. Settings TABLE shows KEYS AND what TO do WITH them, include OR exclude. TABLE DATA has strings that contain different VALUES, SOME OF them include KEYS FROM settings, SOME NOT. IN fact, I'm looking for solution to combine below query in the end:
data as (
select 'value_with_key1_and_other_stuff' as string_with_data union all
select 'value_with_key2_and_other_stuff' as string_with_data union all
select 'value_with_key3_and_other_stuff' as string_with_data union all
select 'value_with_key4_and_other_stuff' as string_with_data union all
select 'value_with_key1_key3_and_other_stuff' as string_with_data union all
select 'just_a_test' as string_with_data
)
select * from data
where (upper(string_with_data) like upper('%key1%') or upper(string_with_data) like upper('%key2%')) and upper(string_with_data) not like upper('%key3%');
But instead of hardcoding keys, I'd LIKE TO USE settings TABLE. How do I achieve that?
Oh, AND my PostgreSQL version :
PostgreSQL 10.8 (Ubuntu 10.8-0ubuntu0.18.04.1) ON x86_64-pc-linux-gnu, compiled BY gcc (Ubuntu 7.3.0-16ubuntu3) 7.3.0, 64-bit