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- #include <stdio.h>
- #include <string.h>
- // Cerinta: Inlocuieste \r\n din char cu \n. Adica, AT+CIMI\r\n\r\n226030162588370\r\n\r\nOK\r\n
- // trebuie sa devina cumva AT+CIMI\n226030162588370\nOK\n
- // Codul transforma AT+CIMI\r\n\r\n226030162588370\r\n\r\nOK\r\n in AT+CIMI\r\n\r\n226030162588370\r\n\r\nOK\r\n
- // si nu am nevoie de asta...
- int main (void) {
- char at[] = "AT+CIMI\r\n\r\n226030162588370\r\n\r\nOK\r\n"; // My AT Command and response
- // Replacer...
- char *source, *destination;
- for (source = destination = at; *source != '\0'; source++) {
- *destination = *source;
- if (*destination != '\r' && *destination != '\n') {
- destination++;
- }
- }
- *destination = '\0'; //make me a great 'string' again
- printf("%s", at); // printf the 'string'...
- }
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