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Mar 29th, 2017
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  1. int nrmaxim(int n)
  2. {
  3. int p=1,aux=n,mmax=n,k=0,i;
  4. while (n>=10)
  5. {
  6.  
  7. p=p*10;
  8. k++;
  9. n=n/10;
  10. }
  11. for (i=1;i<=k;i++)
  12. {
  13. aux=aux%p*10+aux/p;
  14. if(aux>mmax)
  15. mmax=aux;
  16.  
  17. }
  18.  
  19. return mmax;
  20. }
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