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Nov 18th, 2017
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  1. n = 300
  2. r = 0.7
  3.  
  4. largest = 0
  5. nbReps = 5e4
  6. for (i in 1:nbReps)
  7. {
  8. largest = largest + max(rpois(n,r))
  9. }
  10. print(largest / nbReps)
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