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Sep 25th, 2017
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Pascal 0.51 KB | None | 0 0
  1. type seribu=1..1000;
  2.      seseribu=1..100000;
  3.  
  4. var kandidat:array [1..100000] of seseribu;
  5.     angka:array [1..100000] of seribu;
  6.     max,n,i,penghitung:seseribu;
  7.  
  8. begin
  9.  readln(penghitung);
  10.  
  11.  for i:=1 to penghitung do
  12.   begin
  13.    readln(angka[i]);
  14.    inc(kandidat[angka[i]]);
  15.   end;
  16.  
  17.  for i:=1 to penghitung do
  18.   if max<=kandidat[i] then (*karena nilai i menaik, maka akan mencari modus terbanyak dan nilai terbesar*)
  19.    begin
  20.      max:=kandidat[i];
  21.      n:=i*10000;
  22.    end;
  23.  
  24.  writeln(n);
  25. end.
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