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Nov 22nd, 2019
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  1. if (n.Nickname.length() == s.length()) {
  2.  
  3. int l = s.length();
  4.  
  5. for (int i = 0; i < l; i++) {
  6.  
  7. if (n.Nickname[i] != s[i]) {
  8.  
  9. return false;
  10. }
  11. }
  12. }
  13. else return false;
  14.  
  15. return true;
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