import os
def getfilez(dir):

    for name in os.listdir(dir):
        path = os.path.join(dir,name)

        if os.path.isfile(path):
            j = os.path.splitext(path)

            if j[1]=='.txt':
                print path
        else:
            getfilez(path)
m = "C:\Users\6CDG83DFV443RP443RP4\Documents\infodocs"
getfilez(m)


raceback (most recent call last):
  File "C:/Python27/filezz.py", line 15, in <module>
    getfilez(m)
  File "C:/Python27/filezz.py", line 4, in getfilez
    for name in os.listdir(dir):
WindowsError: [Error 123] The filename, directory name, or volume label syntax is incorrect: 'C:\\Users\x06CDG83DFV443RP443RP4\\Documents\\infodocs/*.*'
>>>