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Nov 15th, 2017
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  1. select l.type, count(*)
  2. from login_log l
  3. left join users u on u.id=l.id_user
  4. where u.internal=false
  5. group by l.type
  6.  
  7.  
  8. "twitter";126
  9. "email";9013
  10. "facebook";5727
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