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  1. //Homework 2 Problem 1
  2. //Found on Page 157 of C Programing a Modern Approach
  3.  
  4. #include <stdio.h>
  5. #include <string.h>
  6.  
  7. int main()
  8. {
  9.         char ph_number[15];
  10.         char ph_conv[15];
  11.         int cntr = 0;
  12.         printf("Enter a text phone number (eg. 1-800-ABC-DEFG) press enter when finished entering the phone number\n");
  13.         do
  14.         {
  15.                 scanf("%1c", &ph_number[cntr]);
  16.                 ++cntr;
  17.         }while(ph_number[cntr-1] != '\n');
  18.  
  19.         for(cntr=0; ph_number[cntr]; cntr++)
  20.         {
  21.                 printf("%c, %d, ", ph_number[cntr], (int)ph_number[cntr]);
  22.         }
  23.  
  24.         printf("\n");
  25.         cntr = 0;
  26.        
  27.     //Continually returns 2 for all values for unknown reason
  28.     do
  29.         {
  30.                 if(65 <= (int)ph_number[cntr] <= 67 || 97 <= (int)ph_number[cntr] <= 99){
  31.                         ph_conv[cntr] = '2';}
  32.                 else if(67 < (int)ph_number[cntr] <= 70 || 99 < (int)ph_number[cntr] <= 102){
  33.                         ph_conv[cntr] = '3';}
  34.                 else if(70 < (int)ph_number[cntr] <= 73 || 102 < (int)ph_number[cntr] <= 105){
  35.                         ph_conv[cntr] = '4';}
  36.                 else if(73 < (int)ph_number[cntr] <= 76 || 105 < (int)ph_number[cntr] <= 108){
  37.                         ph_conv[cntr] = '5';}
  38.                 else if(76 < (int)ph_number[cntr] <= 79 || 108 < (int)ph_number[cntr] <= 111){
  39.                         ph_conv[cntr] = '6';}
  40.             else if(79 < (int)ph_number[cntr] <= 83 || 111 < (int)ph_number[cntr] <= 115){
  41.                 ph_conv[cntr] = '7';}
  42.             else if(83 < (int)ph_number[cntr] <= 86 || 116 < (int)ph_number[cntr] <= 118){
  43.                 ph_conv[cntr] = '8';}
  44.             else if(87 < (int)ph_number[cntr] <= 90 || 118 < (int)ph_number[cntr] <= 122){
  45.                     ph_conv[cntr] = '9';}
  46.                 else{ ph_conv[cntr] = ph_number[cntr];}
  47.                 ++cntr;
  48.         }while(ph_number[cntr-1] != '\n');
  49.  
  50.         cntr = 0;
  51.         do
  52.         {
  53.                 printf("%c", (char)ph_conv[cntr]);
  54.                 ++cntr;
  55.         }while(ph_conv[cntr-1]);
  56.  
  57.         printf("\n");
  58.         return(0);
  59. }
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