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acxl

code base version 1.0

Dec 11th, 2020
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text 0.16 KB | None | 0 0
  1. reverse(s.begin(), s.end());
  2. for (int i = s.size() - 1; i >= 0; i--) {
  3. if (s[i] >= '0' && s[i] <= '9')
  4. n += (s[i] - 48) * pow(base, i);
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