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__Sign Up__- Okay so ultimately this isn't as "flashy" as a big numbers dump, but it's easy to understand and given what I've seen from various simulative and permutative efforts I'm comfortable that it's accurate.
- Ultimately, when your sitting at 2PP you will broadly be in one of three scenarios:
- 1 - You only have 1-2 ticks of Minuet left
- 2 - You're likely to Barrage+EA (or EA+Barrage) in the next oGCD window and thus won't be able to PP
- 3 - You have EA coming up in your next oGCD (so presumably after your next tick), but no Barrage so you'll be able to EA->PP if desired
- 4 - None of the above are true, i.e. the "default scenario"
- In order of simplicity:
- On (2), you're basically always going to use a 2PP in this scenario. You're libel to get two ticks before your next chance to PP, not to mention the stack from EA, so you want some room for procs going in. There's no real need to math it, but note that even at 20% crit you have a ~59% chance of getting at least one proc (with EA as the wasted second if you sat at 2 rep), nevermind more procs or more crit.
- On (4), the important point is that if your plan is to 2PP, then in the "win" scenario where you get a double proc, you're also going to use those on a 2PP, which means you deal 480p instead of 420p, for +60p. In the "lose" scenario where you just get a single proc, you deal 420p instead of 240p now and 120-140p later depending on whether your next proc is a single or a double.
- The intersection of that, where you win more on average than you lose, can of course be mathed out - it comes out to 64% or higher. So as expected we'd be looking at openers-only for using 2PP in the default circumstance. Granted we might not quite hit 64% in 3.0/3.1 (takes about 2400-2450 Crit), but may as well get into the habit.
- On (3), you're looking at a shift in the situation above, where instead of getting 0, 1 or 2 procs by your next GCD, you'll get 0+1, 1+1, or 2+1. In the second case, if you react well you can PP-EA, so that's a loss for 2PP and guaranteed to be -60p at that. Moreover the first case also becomes a loss at the scale of a single proc in the above. But the latter becomes a win of +100p instead of +60p, since you can 2PP-GCD-EA-3PP instead of 2PP-GCD-2PP-EA like a fool.
- The intersection here becomes to be to 2PP at 61% or higher. Thankfully so, because it means we can just rope scenario 3 in with scenario 4, effectively ignoring the former.
- Now for (1). If you have one tick left, a single proc following a 2PP becomes a -80p loss, while the gain if you double proc is +60p. The breakpoint on this is 73%, which we aren't seeing any time soon, if ever. So you should never 2PP with Minuet at, say, sub-5s unless it's your last oGCD before Ballad.
- With two ticks left, it gets a bit weird and rabbit hole-y, but we can figure out the odds of different sequences and weigh out the results accorginly. In specific, 2PP "wins" when you get a double proc and a no-proc in some order (+60), or a double proc followed by a single proc (+140). 3PP "wins" when you get a single and a noproc in either order (+80), or two single procs (+40).
- Note that we could do this for three ticks left and so on, but at severe risk to sanity. In any case, for two ticks the breakpoint lands at 54% crit, once again in the land of probably only happening with Litany+CS.
- Sooooo, it turns out we can neatly sum all this 2PP stuff up as follows:
- :: If you have a Bar+EA / EA+Bar coming up in your next GCD, always burn a 2-stack PP.
- :: If you're in the last or second-to-last GCD before leaving Minuet, never use a 2-stack PP.
- :: Otherwise, use PPs at two stacks if and only if you have both Battle Litany and Chain Strategem on your DoTs.

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