a guest Jan 19th, 2019 58 Never
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  1. double calnum(double (*f)(double), double a, double b, int n)
  2. {
  3.        int i;
  4.        double krok = (b-a)/n; //wysokość każdego z trapezów
  5.        double wynik = 0;
  6.        for (i=0; i<n; i++) //zaczynam od zerowego wyrazu
  7.            wynik += (f(x)*f(x+1)krok)/2;
  8.            x += krok;
  9.            }
  10.            return wynik;
  11. }
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