Advertisement
Guest User

Untitled

a guest
Aug 14th, 2019
82
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
text 0.98 KB | None | 0 0
  1. test2 <- test %>% mutate(grouped_id = row_number()) %>%
  2. group_by(BroodID) %>%
  3. summarise_each(funs(na.omit))
  4.  
  5. structure(list(ID = c(2010.3, 2010.3, 2010.3, 2010.3, 2010.33,
  6. 2010.34, 2010.38, 2010.38, 2010.39, 2010.39, 2010.4, 2010.4,
  7. 2010.4, 2010.4, 2010.4, 2010.41, 2010.41, 2010.42, 2010.42, 2010.44,
  8. 2010.44, 2010.46, 2010.46), F = structure(c(5L, 5L, 12L, 12L,
  9. 11L, 8L, NA, 3L, NA, 1L, NA, 2L, 2L, 6L, 6L, NA, 7L, NA, 9L,
  10. NA, 4L, NA, 10L), .Label = c("T206434", "T206553", "T931169",
  11. "T931286", "T961275", "V470937", "X250041", "X250109", "X250195",
  12. "X250568", "X251067", "X251069"), class = "factor"), M = structure(c(2L,
  13. 2L, 11L, 11L, 6L, NA, 9L, NA, 10L, NA, 1L, 1L, 4L, 4L, NA, 8L,
  14. NA, 3L, NA, 7L, NA, 5L, NA), .Label = c("T206824", "T206994",
  15. "T960191", "T961486", "X250567", "X250779", "X250851", "X251046",
  16. "X251066", "X251074", "X251116"), class = "factor")), row.names = c(NA,
  17. 23L), class = "data.frame")
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement