interface Sentence {
  start: number
  end: number
}

const outputExample = [
  { start: 0, end: 28 },
  { start: 29, end: 117 },
  { start: 118, end: 145 },
  { start: 146, end: 196 },
  { start: 197, end: 229 },
  { start: 230, end: 233 },
  { start: 234, end: 303 }
]

/**
 * Implement a function that takes a text as input and returns an array of
 * sentence ranges.
 *
 * Your solution will be validated against an extended data set :)
 */
export function splitter(text: string): Sentence[] {
  let output = [];
  let start = 0, end = 0, lvlBrackets = 0;
  const regex = new RegExp('[ A-Z]+');
  const spaces = new RegExp('\\s');

  for(let i = 0; i < text.length; i++) {
    if(text[i] == '"') {
      if(lvlBrackets == 1) {
        lvlBrackets = 0;
		let next_symbol = i + 1;
        while(spaces.test(text[next_symbol])) {
          next_symbol += 1;
        }
        if (regex.test(text[next_symbol]) {
          output.push({start, end: i+1});
          start = next_symbol;
          continue;
        }
      }
      else {
        lvlBrackets = 1;

      }
    }
    else if(i == text.length - 1 ||
        (
          (text[i] == '.' || text[i] == '?' || text[i] == '!' ) &&
          spaces.test(text[i+1]) &&
          // (i + 2 >= text.length || (text[i+2] !== ' ' && text[i+2] !== '.')) &&
          // text[i+1] !== '.' &&
          !lvlBrackets &&
          !(text[i-2] == 'M' && text[i-1] == 's') &&
          !(text[i-2] == 'M' && text[i-1] == 'r') &&
          !(text[i-3] == 'M' && text[i-2] == 'r' && text[i-1] != 's') &&
          !(text[i-4] == 'M' && text[i-3] == 'i' && text[i-2] == 's' && text[i-1] != 's')
        )
      ) {
      end = i + 1;
      output.push({start, end});

      start = i + 2;
      while(spaces.test(text[start])) {
        start += 1;
      }
      end = 0;
    }
  }
  for(let j in output) {
    let t = "";
    for(let k = output[j].start; k <= output[j].end; k++) {
      t+=text[k];
    }
    console.log(t);
    console.log("+++++++++++++");
  }
  return output;
}