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Aug 20th, 2019
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  1. // changed noting methodology to writing notes within the code with comments. Went through each line and added a note saying what it does, and also did a variety of testing with console.log(); on things I was unsure about. Tested the functions at the end and found it working.
  2.  
  3. function getTokens(rawString) {
  4. // a named function called getTokens with a single argument (rawString)
  5. // NB: `.filter(Boolean)` removes any falsy items from an array
  6. return rawString.toLowerCase().split(/[ ,!.";:-]+/).filter(Boolean).sort();
  7. //any text used in the rawString argument is changed to lowercase. .toLowercase() is a built in method in JS
  8. // .split() is a built in method that is used here to separate each word that might be separated by white space or special characters.
  9. // .filter(Boolean) is a built in method removes falsy entries from the array and .sort() with no argument will sort words alphabetically
  10. }
  11.  
  12. function mostFrequentWord(text) {
  13. // establishes a named function called mostFrequentWord with the single argument (text)
  14. let words = getTokens(text);
  15. // establishes the variable called words and calls the getTokens(text) function explained earlier
  16. let wordFrequencies = {};
  17. // establishes an empty object called wordFrequencies
  18. for (let i = 0; i <= words.length; i++) {
  19. // a for loop using the standard 3 arguments: let i = 0; is the initialized counter variable, i <= words.length; is the condition by which it is told to continue; i++ dictates how the counter is to be incremented, so each time the loop happens i increases by 1.
  20. if (words[i] in wordFrequencies) {
  21. wordFrequencies[words[i]]++;
  22. // if statement that if the current word (starting with words[0]) is in wordFrequencies already, then increment 1 to that number.
  23. } else {
  24. wordFrequencies[words[i]] = 1;
  25. //else statement used so that if words[i] is not in wordFrequncies yet, it's count is set to 1
  26. }
  27. }
  28. let currentMaxKey = Object.keys(wordFrequencies)[0];
  29. // This line uses the built in Object.keys() to go through the wordFrequencies object and create an array of all of the keys in it. It creates a variable called currentMaxKey at [0] to start at the beginning.
  30. console.log(currentMaxKey);
  31. // This returns 'a' because the text is sorted in alphabetical order
  32. let currentMaxCount = wordFrequencies[currentMaxKey];
  33. // a variable named currentMaxCount which accesses the wordFrequencies object and calls whichever item number is aligned to the number of currentMaxKey
  34.  
  35. for (let word in wordFrequencies) {
  36. // creates a for loop that is used to iterate through all of the words in wordFrequencies
  37. if (wordFrequencies[word] > currentMaxCount) {
  38. // if statement that looks for any wordFrequencies that are greater than the currentMaxCount variable established earlier
  39. currentMaxKey = word;
  40. // if it finds one, then currentMaxKey is changed to that new word
  41. currentMaxCount = wordFrequencies[word];
  42. // sets the new currentMaxCount to the number of uses of that word
  43. }
  44. console.log(currentMaxKey);
  45. console.log(currentMaxCount);
  46. }
  47. return currentMaxKey;
  48. }
  49.  
  50. console.log(mostFrequentWord('I am testing this function to make sure it is working. Testing a function like this can be rewarding because I like testing things. Testing is one of the best things you can do'));
  51. // printed => testing
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