CodingParina.cpp

#include <bits/stdc++.h>
using namespace std;


template<class integer>
inline integer to_int(const string& s, size_t* idx = 0, int base = 10) {
    size_t n = s.size(), i = idx ? *idx : 0; bool sign = false; integer x = 0;
    if (s[i] == '-')
        ++i, sign = true;
    function<int(char)> char_to_digit = [&](char c) {
        static const int d[] = {'a'-10,'0'};
        return tolower(c)-d[isdigit(c)]; };
    while (i < n)
        x *= base, x += char_to_digit(s[i++]);
    if (idx)
        *idx = i;
    return sign ? -x : x; }

template<class integer>
inline string to_string(integer x, int base = 10) {
    bool sign = false; string s;
    if (x < 0)
        x = -x, sign = true;
    function<char(int)> digit_to_char = [](int d) {
        static const char c[] = {'a'-10,'0'};
        return c[d < 10]+d; };
    do
        s += digit_to_char(x%base), x /= base;
    while (x > 0);
    if (sign)
        s += '-';
    reverse(s.begin(),s.end());
    return s; }

template<class integer>
inline istream& read(istream& is, integer& x) {
    string s; is >> s, x = to_int<integer>(s); return is; }

template<class integer>
inline ostream& write(ostream& os, integer x) { return os << to_string(x); }

using  lll =   signed __int128;
using ulll = unsigned __int128;

inline istream& operator>>(istream& is,  lll &x) { return  read(is,x); }
inline istream& operator>>(istream& is, ulll &x) { return  read(is,x); }
inline ostream& operator<<(ostream& os,  lll  x) { return write(os,x); }
inline ostream& operator<<(ostream& os, ulll  x) { return write(os,x); }


int main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(NULL);
    const ulll one=(ulll)1;///using 1 as ulll 1
    const ulll zero=(ulll)0;///using 0 as ulll 0
    const ulll two=(ulll)2;///using 2 as ulll 2
    ///This is being used to prevent errors in comparison between 2 different data types
    int n;
    cin>>n;
    while(n--)
    {
        ulll x;
        cin>>x;
        ulll fact=one;
        ulll i;///since i is being used in calculations such as division by i*(i+1)
        ///if i is of a different data type dividing ulll data with int may result in error
        if(x==one)
        {
            cout<<one;///ostream(output stream) is of ull constant to represent 1, unnecessary edit
            cout<<'\n';///this endline works for when 1 is to be printed
            continue;

        }
        for(i=two;;i+=two)///the loop variable is ulll so it starts and increments with an ulll value so as to prevent errors due to combining 2 different data types for an arithmetic operation
        {

            x=x/(i*(i+one));///this is the main reason for using i as ulll
            if(x==one)
            {
                cout<<i+one;///one used here for the same reason to prevent errors due to performing arithmetic operations between 2 different data types
                break;
            }
            if(x==zero)
            {
                cout<<i;
                break;
            }

        }
       cout<<'\n';///this endline works for everyone except when 1 is to be printed

    }


}