Given :-
• Product of two rational number=2
• First number=1/7
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★ To find :-
• 2nd rational number to be multiplied by 1/7 and give product 1/7.
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★ Solution :-
Let us assume the required number be x.

Now,the equation can be created as follows::

[tex]\sf :\implies( x)\times\dfrac{1}{7}=2[/tex]

Now multiplying both sides by 7::

[tex]\sf :\implies( x)\times\dfrac{1}{7}\times 7=2\times 7[/tex]

Now, 7 will be cancelled in LHS whereas will be simplified on RHS::

[tex]\sf :\implies( x)\times\dfrac{1}{\not 7}\times\not 7=2\times 7[/tex]

[tex]\sf :\implies x\times1=2\times 7[/tex]

[tex]\sf :\implies x=2\times 7[/tex]

Required Answer::

[tex]\Large\boxed{\sf :\implies x=14}[/tex]

So the other number is 14.
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★ Verification :-

Let's verify our result::
In the Question it is given that product of 2 numbers is 2 of which first no. Is 1/7 and we were asked to find 2nd number. The 2nd number is obtained by above method which is 14 and now we are going to verify our result.

So,

[tex]\sf :\implies (First\: number)\times(2nd \: number)=2[/tex]

[tex]\sf :\implies (14)\times\bigg(\dfrac{1}{7}\bigg)=2[/tex]

[tex]\sf :\implies 14\times\dfrac{1}{7}=2[/tex]

[tex]\sf :\implies 2=2[/tex]

Since LHS=RHS, our answer is correct!!

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