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Jun 25th, 2018
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C++ 0.34 KB | None | 0 0
  1.     // Declare even counter and length of array
  2.     int evencount;
  3.     int len = sizeof(myArray)/sizeof(myArray[0]);
  4.     // Traverse through array
  5.     for (int i=0;i<len;i++)
  6.     {
  7.         // If current value is even, increase counter by 1
  8.         if (myArray[i] % 2 == 0)
  9.         {
  10.             evencount++;
  11.         }
  12.     }
  13.     // Output number of even numbers
  14.     cout << evencount << endl;
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