moment of inertia of rod about its center of mass, Icm = m*L^2/12


moment of inertia of rod about one end(Using parallel axis theorm),

I = Icm + m*d^2 (d is the distance from center to end)

= m*L^2/12 + m*(L/2)^2

= m*L^2/12 + m*L^2/4

= (m*L^2 + 3*m*L^2)/12

= m*L^2/3

= 2.31*0.85^2/3

= 0.556 kg.m^2 <<<<<<<<<<<<------------Answer