(in twitterapp)

public boolean login(String userName, String password)
    {
        boolean LogIn = false;
        if(users.size() == 0)
        {
            LogIn = false;
        }
        else
        if(currentUser == null)
        {
            Iterator<User> it = users.iterator();
            {
                while(it.hasNext())
                {
                    User user = it.next();
                    String NameToLogIn = user.getUserName();
                    if(userName.equals(NameToLogIn))
                    {
                        if(user.getPassWord().equals(password))
                        {
                            currentUser = user;
                            LogIn = true;
                        }
                        else
                        {
                            LogIn = false;
                        }
                    }
                    else
                    {
                        LogIn = false;
                    }
                }
            }
        }
        else
        {
            LogIn = false;
        }
        return LogIn;
    }

(in twittertextui)
if(commandWord.equals("login"))
        {
            int ParameterWords = TotalNumberOfWords - NumberOfCommandWords;
            if(twitterapp.getNumberOfUsers() == 0)
            {
                System.out.println("There are no users yet. Please make an account.");
            }
            else
            {
                if(ParameterWords == 2)
                {
                    if(twitterapp.getcurrentuser() == null)
                 Moet hier nog een lust komen die nagaat of de username en password overeenkomen?nee  toch he? want dat wordt nagekeken in twitterapp.login(..)
                    {
                        String userName = words.get(NumberOfCommandWords);
                        String password = words.get(NumberOfCommandWords+1);
                        twitterapp.login(userName,password);
                        if((twitterapp.login(userName,password)) == true)               // hier gaat hij altijd naar het else-gedeelte, hoewel de methode in twitterapp 'true' is
                        {
                            System.out.println("You were logged in successfully!");
                        }
                        else
                        {
                            System.out.println("Password and username didn't match!");
                        }
                    }
                    else
                    {
                        System.out.println("Please first logout");
                    }
                }

                else
                {
                    System.out.println("Please type the required number of words.");
                    System.out.println("Please type help for instructions.");
                }