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Nov 13th, 2019
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  1.  
  2. //проверка ацикличности графа. если cycle - true - цикл есть.
  3. void dfs(int v, vector < vector < int>>& mas, vector < char>& colors, bool& cycle) {
  4.     if (colors[v] == 'G') {
  5.         cycle = true;
  6.         return;
  7.     }
  8.     else if (colors[v] == 'B') {
  9.         return;
  10.     }
  11.     else {
  12.         colors[v] = 'G';
  13.     }
  14.      //проверка всех ребер исходящих от mas[v]
  15.     for (int soldat : mas[v]) {
  16.         dfs(soldat, mas, colors, cycle);
  17.     }
  18.     colors[v] = 'B';
  19. }
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