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a guest Jun 19th, 2017 51 Never
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  1. Fe(s) + 3/2 Br2 (l) -> FeBr3 (s)   dH = -269 kJ/mol
  2. which gives
  3. 2 Fe (s) + 3 Br2 (l) -> 2 FeBr3 (s)  dH = -538 kJ/mol  (1)
  4.  
  5. you're also given
  6. 2 Fe (s) + 3 Br2 (g) -> 2 FeBr3 (s)  dH = -631 kJ/mol
  7. so you can write
  8. 2 FeBr3 (s) -> 2 Fe (s) + 3 Br2 (g)  dH = +631 kJ/mol  (2)
  9.  
  10. Now add (1) and (2):
  11.  
  12. 3 Br2 (l) -> 3 Br2 (g)  dH = -538 + 631 = +93 kJ/mol
  13. which gives
  14. Br2 (l) -> Br2 (g)    dH = +31 kJ/mol
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