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Jul 21st, 2017
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  1. tmp=[]
  2. smallest = []
  3. for i in range(len(pepes):
  4. tmp.append((pepes[i] , pepes.count(pepes[i]))
  5. smallest.append(tmp(1))
  6. for k in range(len(smallest):
  7. if smallest[0]>smallest[k]:
  8. smallest[0],smallest[k] = smallest[k],smallest[0]
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