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Jul 27th, 2016
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PHP 0.92 KB | None | 0 0
  1. <?php
  2.     $username = "db_smap";
  3.     $password = "fsdvsdcsdcsdcsd";
  4.     $hostname = "mysql.ukraine.com.ua";
  5.    
  6.     //connection to the database
  7.     $dbhandle = mysql_connect($hostname, $username, $password)
  8.      or die("Unable to connect to MySQL");
  9.     echo "Connected to MySQL<br>";
  10.    
  11.     //select a database to work with
  12.     $selected = mysql_select_db("lemon00_smap",$dbhandle)
  13.       or die("Could not select DB");
  14.    
  15.     //execute the SQL query and return records
  16.     $result = mysql_query("SELECT id, alias, catid, created FROM pvj5q_k2_items WHERE created LIKE '%2016%'");
  17.    
  18.    
  19.     //Нужно получить еще алиас категории
  20.     //mysite.com/news/[site_categories|alias]/[site_posts|ID]-[site_posts|alias]
  21.     //fetch tha data from the database
  22.     while ($row = mysql_fetch_array($result)) {
  23.        echo "http://mysite.com/news/".$row{'id'}."-".$row{'alias'}."<br>" ;
  24.     }
  25.    
  26.    
  27.     //close the connection
  28.     mysql_close($dbhandle);
  29. ?>
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