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Apr 17th, 2018
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  1. <form method="post" action="login.php" onsubmit="validateForm()" id="loginForm" name="loginForm">
  2.  
  3.  
  4. Name:<br>
  5.  
  6. <input type="text" name="personName"><br>
  7.  
  8. Password:<br>
  9.  
  10. <input type="password" name="pswd"><br>
  11.  
  12. <input type="submit" name="submit" id="submit" value="Login" />
  13.  
  14. </form>
  15.  
  16. <script>
  17. function validateForm()
  18. {
  19. var n = document.loginForm.personName.value;
  20. var p = document.loginForm.pswd.value;
  21. //The var below is what I need help on.
  22. var name = "<?php echo $row['name']; ?>";
  23. //The var below is what I need help on.
  24. var ps = "<?php echo $row['pwd']; ?>";
  25. if ((n == name) && (p == ps))
  26. {
  27. alert ("Login successful!");
  28. return true;
  29. }
  30. else
  31. {
  32. alert ("Login failed! Username or password is incorrect!");
  33. return false;
  34. }
  35. }
  36. </script>
  37.  
  38. <?php
  39.  
  40. function validateLogin()
  41. {
  42. //I hid this information from here.
  43. $servername = "";
  44. $username = "";
  45. $password = "";
  46. $dbname = "";
  47.  
  48. // Create connection
  49. $dbc = new mysqli($servername, $username, $password, $dbname);
  50. // Check connection
  51. if ($dbc->connect_error)
  52. {
  53. die("Connection failed: " . $dbc->connect_error);
  54. }
  55.  
  56.  
  57. $n = $_POST["personName"];
  58. $p = $_POST["pswd"];
  59.  
  60.  
  61. $query = "SELECT `name`, `pwd` FROM `chatApp`";
  62. $result = $dbc->query($query);
  63.  
  64. $numRows = mysql_num_rows($result);
  65.  
  66. $count = 1;
  67.  
  68. if ($result->num_rows > 0)
  69. {
  70.  
  71. while($row = $result->fetch_assoc())
  72. {
  73.  
  74.  
  75.  
  76. }
  77.  
  78. }
  79. else
  80. {
  81. echo "0 results";
  82. }
  83.  
  84. $dbc->close();
  85.  
  86. }
  87.  
  88. if(array_key_exists('loginForm',$_POST))
  89. {
  90. validateLogin();
  91. }
  92.  
  93. ?>
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