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Aug 24th, 2019
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PHP 0.38 KB | None | 0 0
  1. $db = mysqli_connect("localhost", "root", "", "dbname"); // keep your db name
  2. $sql = "YOUR SQL CODE FOR RETRIEVING THE RECORD WHICH HOLDS YOUR IMAGE CONTENT";
  3. $sth = $db->query($sql);
  4. $result = mysqli_fetch_array($sth);
  5. echo '<img src="data:image/jpeg;base64,'.base64_encode( $result['image'] ).'"/>'; // ASSUME THAT "image" IS THE NAME OF YOUR COLUMN WHICH HOLDS DATA ABOUT YOUR IMAGE
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