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Feb 13th, 2016
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  1. solve n = do
  2.     let c k = genericLength $ filter (\x -> x^3 `mod` k == 1) [1..k-1]
  3.     let (xs, ys) = partition ((==3) . c) primes
  4.     a <- xs
  5.     guard (a <= n)
  6.     return a
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