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SteelK

Untitled

Dec 9th, 2016
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C++ 0.18 KB | None | 0 0
  1.     long double yk = 0, sum = 0, iter = 0, mas2[100];
  2.     while (iter <= k){
  3.         for (int i = 0; i <= k; i++){
  4.             sum += mas[1][i];
  5.         }
  6.         mas2[i] = ((b - a) / n) * sum;
  7.         iter++;
  8.     }
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