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By: a guest on Apr 17th, 2012  |  syntax: None  |  size: 0.18 KB  |  hits: 7  |  expires: Never
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  1. ;; sbochins's solution to http://4clojure.com/problem/26
  2.  
  3. #(loop [n1 1 n2 0 cnt 0 out '()]
  4.     (if (>= cnt %)
  5.       (reverse out)
  6.     (recur (+ n1 n2) n1 (inc cnt) (cons n1 out))))
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