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SteelK

Untitled

Dec 9th, 2016
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C++ 0.29 KB | None | 0 0
  1. for (int i = 0; i <= k-1; i++)
  2.         mas3[i] = (mas2[i+1] - mas2[i]) / ((b - a) / n);
  3.    
  4.     int iterEndl = 0;
  5.     for (int i = 0; i <= k; i++){
  6.             cout << " " << mas[0][i] << ": " << mas3[i] << "\t";
  7.             iterEndl++;
  8.         if (iterEndl == 2){
  9.             cout << endl;
  10.             iterEndl = 0;
  11.         }
  12.     }
  13.     return 0;
  14. }
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