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Get int from char[] of bytes
FILE * file = fopen("file");
char buffer[size];
fread(buffer,1,size,file);
int = buffer[0x8]; // What should I do here?
// I imagine it involves some strange pointer
// arithmetic but I can't see what I should do,
// casting to int just takes the first byte,
// casting to (int *) doesn't compile

int foo = *((int *) &buffer[0x8]);

#include <stdio.h>

main() {
    char buffer[14] = { 0,1,2,3,4,5,6,7,8,9,10,11,12,13 };
    int foo = *((int *) &buffer[0x8]);
    int bar = (int) buffer[0x8];

    printf("raw: %dn", buffer[8]);
    printf("foo: %dn", foo);
    printf("bar: %dn", bar);
}

raw: 8
foo: 185207048
bar: 8

int x = *(int *)&buffer[8];

int x = buffer[8] + (buffer[9] << 8) + (buffer[10] <<  16) + (buffer[11] << 24);

int val = 0x00000000;
char* ptr = reinterpret_cast<char*>(&val);
*ptr = buffer[0x0a];
ptr++;
*ptr = buffer[0x0b];
ptr++;
*ptr = buffer[0x08];
ptr++;
*ptr = buffer[0x09];
ptr++;

int *list = (int*)buffer;
int n = fread(buffer, 1, size, file);
for (int i=0; i< n/sizeof(int); i++)
  printf("%dn", list[i]);