import java.io.*;
import java.util.*;

public class QuicksortKiller implements Runnable {

	final boolean ONLINE_JUDGE = System.getProperty("ONLINE_JUDGE") != null;
	
	PrintWriter out;
	
	@Override
	public void run() {
		try {
			if (ONLINE_JUDGE) {
				out = new PrintWriter(System.out);
			} else {
				out = new PrintWriter("output.txt");
			}
			Locale.setDefault(Locale.US);
			solve();
			out.close();
		} catch (Throwable e) {
			e.printStackTrace(System.err);
			System.exit(-1);
		}
	}
	
	public static void main(String[] args) {
		new Thread(null, new QuicksortKiller(), "", 256 * 1024 * 1024).start();
	}
	
//------------------------------------------------------------------------------

	final int INSERTION_SORT_THRESHOLD = 47;
	
	private void hackedSort(int[] a, int left, int right, boolean leftmost) {
        int length = right - left + 1;

        // Use insertion sort on tiny arrays
        if (length < INSERTION_SORT_THRESHOLD) {
            if (leftmost) {
            	
            	for (int i = left; i <= right; i++) {
            		if (a[i] == Integer.MIN_VALUE) a[i] = maxNum--;
            	}

                /*
                 * Traditional (without sentinel) insertion sort,
                 * optimized for server VM, is used in case of
                 * the leftmost part.
                 */
                for (int i = left, j = i; i < right; j = ++i) {
                    int ai = a[i + 1];
                    int pi = p[i + 1];
                    while (ai < a[j]) {
                        a[j + 1] = a[j];
                        p[j + 1] = p[j];
                        if (j-- == left) {
                            break;
                        }
                    }
                    a[j + 1] = ai;
                    p[j + 1] = pi;
                }
            } else {
            	
            	for (int i = left+1; i <= right; i++) {
            		if (a[i] == Integer.MIN_VALUE) a[i] = maxNum--;
            	}
            	if (a[left] == Integer.MIN_VALUE) a[left] = maxNum--;

                /*
                 * Skip the longest ascending sequence.
                 */
                do {
                    if (left >= right) {
                        return;
                    }
                } while (a[++left] >= a[left - 1]);

                /*
                 * Every element from adjoining part plays the role
                 * of sentinel, therefore this allows us to avoid the
                 * left range check on each iteration. Moreover, we use
                 * the more optimized algorithm, so called pair insertion
                 * sort, which is faster (in the context of Quicksort)
                 * than traditional implementation of insertion sort.
                 */
                for (int k = left; ++left <= right; k = ++left) {
                    int a1 = a[k], a2 = a[left];
                    int p1 = p[k], p2 = p[left];

                    if (a1 < a2) {
                        a2 = a1; a1 = a[left];
                        p2 = p1; p1 = p[left];
                    }
                    while (a1 < a[--k]) {
                        a[k + 2] = a[k];
                        p[k + 2] = p[k];
                    }
                    ++k;
                    a[k + 1] = a1;
                    p[k + 1] = p1;

                    while (a2 < a[--k]) {
                        a[k + 1] = a[k];
                        p[k + 1] = p[k];
                    }
                    a[k + 1] = a2;
                    p[k + 1] = p2;
                }
                int last = a[right];
                int plast = p[right];

                while (last < a[--right]) {
                    a[right + 1] = a[right];
                    p[right + 1] = p[right];
                }
                a[right + 1] = last;
                p[right + 1] = plast;
            }
            return;
        }

        // Inexpensive approximation of length / 7
        int seventh = (length >> 3) + (length >> 6) + 1;

        /*
         * Sort five evenly spaced elements around (and including) the
         * center element in the range. These elements will be used for
         * pivot selection as described below. The choice for spacing
         * these elements was empirically determined to work well on
         * a wide variety of inputs.
         */
        int e3 = (left + right) >>> 1; // The midpoint
        int e2 = e3 - seventh;
        int e1 = e2 - seventh;
        int e4 = e3 + seventh;
        int e5 = e4 + seventh;
        
        if (a[e1] == Integer.MIN_VALUE) a[e1] = maxNum--;
        if (a[e2] == Integer.MIN_VALUE) a[e2] = maxNum--;
        if (a[e3] == Integer.MIN_VALUE) a[e3] = maxNum--;
        if (a[e4] == Integer.MIN_VALUE) a[e4] = maxNum--;
        if (a[e5] == Integer.MIN_VALUE) a[e5] = maxNum--;

        // Sort these elements using insertion sort
        if (a[e2] < a[e1]) { 
        	int t = a[e2]; a[e2] = a[e1]; a[e1] = t;
        	int pt= p[e2]; p[e2] = p[e1]; p[e1] = pt;
        }

        if (a[e3] < a[e2]) {
        	int t = a[e3]; a[e3] = a[e2]; a[e2] = t;
        	int pt= p[e3]; p[e3] = p[e2]; p[e2] = pt;
            if (t < a[e1]) {
            	a[e2] = a[e1]; a[e1] = t;
            	p[e2] = p[e1]; p[e1] = pt;
            }
        }
        if (a[e4] < a[e3]) {
        	int t = a[e4]; a[e4] = a[e3]; a[e3] = t;
        	int pt= p[e4]; p[e4] = p[e3]; p[e3] = pt;
            if (t < a[e2]) {
            	a[e3] = a[e2]; a[e2] = t;
            	p[e3] = p[e2]; p[e2] = pt;
                if (t < a[e1]) {
                	a[e2] = a[e1]; a[e1] = t;
                	p[e2] = p[e1]; p[e1] = pt;
                }
            }
        }
        if (a[e5] < a[e4]) {
        	int t = a[e5]; a[e5] = a[e4]; a[e4] = t;
        	int pt= p[e5]; p[e5] = p[e4]; p[e4] = pt;
            if (t < a[e3]) {
            	a[e4] = a[e3]; a[e3] = t;
            	p[e4] = p[e3]; p[e3] = pt;
                if (t < a[e2]) {
                	a[e3] = a[e2]; a[e2] = t;
                	p[e3] = p[e2]; p[e2] = pt;
                    if (t < a[e1]) {
                    	a[e2] = a[e1]; a[e1] = t;
                    	p[e2] = p[e1]; p[e1] = pt;
                    }
                }
            }
        }

        // Pointers
        int less  = left;  // The index of the first element of center part
        int great = right; // The index before the first element of right part

        if (a[e1] != a[e2] && a[e2] != a[e3] && a[e3] != a[e4] && a[e4] != a[e5]) {
            /*
             * Use the second and fourth of the five sorted elements as pivots.
             * These values are inexpensive approximations of the first and
             * second terciles of the array. Note that pivot1 <= pivot2.
             */
            int pivot1 = a[e2]; int ppivot1 = p[e2];
            int pivot2 = a[e4]; int ppivot2 = p[e4];

            /*
             * The first and the last elements to be sorted are moved to the
             * locations formerly occupied by the pivots. When partitioning
             * is complete, the pivots are swapped back into their final
             * positions, and excluded from subsequent sorting.
             */
            a[e2] = a[left];  p[e2] = p[left];
            a[e4] = a[right]; p[e4] = p[right];

            /*
             * Skip elements, which are less or greater than pivot values.
             */
            while (a[++less] < pivot1);
            while (a[--great] > pivot2);

            /*
             * Partitioning:
             *
             *   left part           center part                   right part
             * +--------------------------------------------------------------+
             * |  < pivot1  |  pivot1 <= && <= pivot2  |    ?    |  > pivot2  |
             * +--------------------------------------------------------------+
             *               ^                          ^       ^
             *               |                          |       |
             *              less                        k     great
             *
             * Invariants:
             *
             *              all in (left, less)   < pivot1
             *    pivot1 <= all in [less, k)     <= pivot2
             *              all in (great, right) > pivot2
             *
             * Pointer k is the first index of ?-part.
             */
            outer:
            for (int k = less - 1; ++k <= great; ) {
                int ak = a[k];
                int pk = p[k];
                if (ak < pivot1) { // Move a[k] to left part
                    a[k] = a[less];
                    p[k] = p[less];
                    /*
                     * Here and below we use "a[i] = b; i++;" instead
                     * of "a[i++] = b;" due to performance issue.
                     */
                    a[less] = ak;
                    p[less] = pk;
                    ++less;
                } else if (ak > pivot2) { // Move a[k] to right part
                    while (a[great] > pivot2) {
                        if (great-- == k) {
                            break outer;
                        }
                    }
                    if (a[great] < pivot1) { // a[great] <= pivot2
                        a[k] = a[less];
                        p[k] = p[less];
                        a[less] = a[great];
                        p[less] = p[great];
                        ++less;
                    } else { // pivot1 <= a[great] <= pivot2
                        a[k] = a[great];
                        p[k] = p[great];
                    }
                    /*
                     * Here and below we use "a[i] = b; i--;" instead
                     * of "a[i--] = b;" due to performance issue.
                     */
                    a[great] = ak;
                    p[great] = pk;
                    --great;
                }
            }

            // Swap pivots into their final positions
            a[left]  = a[less  - 1]; a[less  - 1] = pivot1;
            p[left]  = p[less  - 1]; p[less  - 1] = ppivot1;
            a[right] = a[great + 1]; a[great + 1] = pivot2;
            p[right] = p[great + 1]; p[great + 1] = ppivot2;

            
            // Sort left and right parts recursively, excluding known pivots
            hackedSort(a, left, less - 2, leftmost);
            hackedSort(a, great + 2, right, false);

            /*
             * If center part is too large (comprises > 4/7 of the array),
             * swap internal pivot values to ends.
             */
            if (less < e1 && e5 < great) {
            	throw new RuntimeException();
            }

            // Sort center part recursively
            hackedSort(a, less, great, false);

        } else { // Partitioning with one pivot
        	throw new RuntimeException();
        }
    }
	
	int maxNum;
	int[] p;
	
	int[] killJava7Quicksort(int n) {
		maxNum = n;
		p = new int[n];
		int[] t = new int[n];
		for (int i = 0; i < n; i++)	{
			p[i] = i;
			t[i] = Integer.MIN_VALUE;
		}
		hackedSort(t, 0, n-1, true);
		validate(p, n, 0, n-1);
		validate(t, n, 1, n);
		int[] a = new int[n];
		for (int i = 0; i < n; i++) {
			a[p[i]] = t[i];
		}
		validate(a, n, 1, n);
		return a;
	}
	
	void print(int[] a, int n) {
		out.println(n);
		for (int i = 0; i < n; i++) {
			out.print(a[i]);
			if (i == n-1) out.println(); else out.print(" ");
		}
	}

	void validate(int[] a, int n, int L, int R) {
		boolean[] used = new boolean[n];
		for (int x : a) {
			if (x < L || R < x) {
				throw new RuntimeException();
			}
			if (used[x - L]) {
				throw new RuntimeException();
			}
			used[x - L] = true;
		}
	}
	
	void solve() throws IOException {
		long t1, t2;
		int[] a;
		
		// TODO
		// 1. enter size of the array to variable n
		// 2. if property ONLINE_JUDGE is not defined on your local computer it outputs array in file output.txt
		// 3. don't forget to comment 'System.out.println()' and 'Arrays.sort()' calls before submit
		// 4. it may not work for some values of n because there's a bug somewhere, so check if sort really works slow before submit
		int n = 100000;
		
		{
			t1 = System.currentTimeMillis();
			a = killJava7Quicksort(n);
			t2 = System.currentTimeMillis();
			System.out.println("Generation takes " + (t2-t1) + " ms");
		}
		
		print(a, n);
		
		{
			t1 = System.currentTimeMillis();
			Arrays.sort(a);
			t2 = System.currentTimeMillis();
			System.out.println("Sort takes " + (t2-t1) + " ms");
		}
		
		System.out.println("Thank you for using Quicksort Killer");
	}

}