i'm back with another longish question. having experimented with a number of Python-based Damerau-Levenshtein edit distance implementations, [i finally found the one listed below][1] as ``editdistance_reference()``. it seems to deliver correct results and appears to have an efficient implementation. [1]: http://mwh.geek.nz/2009/04/26/python-damerau-levenshtein-distance/ so i set down to convert the code to Cython. on my test data, the reference method manages to deliver results for 11,000 comparisons (for pairs of words aound 12 letters long), while the Cythonized method does over 200,000 comparisons per second. sadly, the results are incorrect: when you look at the variable ``thisrow`` which i print out for debugging, my version has it filled with ones no matter what data i throw at it, while the reference output shows another picture. for example, testing ``'helo'`` against ``'world'`` produces the following output (``ED`` marks my function, ``EDR`` is the correctly working reference): from ``editdistance()``: #ED A [0, 0, 0, 0, 0, 1] #ED B [1, 0, 0, 0, 0, 1] #ED B [1, 1, 0, 0, 0, 1] #ED B [1, 1, 1, 0, 0, 1] #ED B [1, 1, 1, 1, 0, 1] #ED B [1, 1, 1, 1, 1, 1] #ED A [0, 0, 0, 0, 0, 2] #ED B [1, 0, 0, 0, 0, 2] #ED B [1, 1, 0, 0, 0, 2] #ED B [1, 1, 1, 0, 0, 2] #ED B [1, 1, 1, 1, 0, 2] #ED B [1, 1, 1, 1, 1, 2] #ED A [0, 0, 0, 0, 0, 3] #ED B [1, 0, 0, 0, 0, 3] #ED B [1, 1, 0, 0, 0, 3] #ED B [1, 1, 1, 0, 0, 3] #ED B [1, 1, 1, 1, 0, 3] #ED B [1, 1, 1, 1, 1, 3] #ED A [0, 0, 0, 0, 0, 4] #ED B [1, 0, 0, 0, 0, 4] #ED B [1, 1, 0, 0, 0, 4] #ED B [1, 1, 1, 0, 0, 4] #ED B [1, 1, 1, 1, 0, 4] #ED B [1, 1, 1, 1, 1, 4] from ``editdistance_reference()``: #EDR A [0, 0, 0, 0, 0, 1] #EDR B [1, 0, 0, 0, 0, 1] #EDR B [1, 2, 0, 0, 0, 1] #EDR B [1, 2, 3, 0, 0, 1] #EDR B [1, 2, 3, 4, 0, 1] #EDR B [1, 2, 3, 4, 5, 1] #EDR A [0, 0, 0, 0, 0, 2] #EDR B [2, 0, 0, 0, 0, 2] #EDR B [2, 2, 0, 0, 0, 2] #EDR B [2, 2, 3, 0, 0, 2] #EDR B [2, 2, 3, 4, 0, 2] #EDR B [2, 2, 3, 4, 5, 2] #EDR A [0, 0, 0, 0, 0, 3] #EDR B [3, 0, 0, 0, 0, 3] #EDR B [3, 3, 0, 0, 0, 3] #EDR B [3, 3, 3, 0, 0, 3] #EDR B [3, 3, 3, 3, 0, 3] #EDR B [3, 3, 3, 3, 4, 3] #EDR A [0, 0, 0, 0, 0, 4] #EDR B [4, 0, 0, 0, 0, 4] #EDR B [4, 4, 0, 0, 0, 4] #EDR B [4, 4, 4, 0, 0, 4] #EDR B [4, 4, 4, 4, 0, 4] #EDR B [4, 4, 4, 4, 4, 4] i must be very dumb as the error is probably one of those very very obvious things. but i can't seem to find it. there is a second problem: i ``malloc`` space for the three arrays ``twoago``, ``oneago``, and ``thisrow``, then they get swapped around in a circular fashion. when i try to ``free( twoago )`` and so on, i get a line where glibc complains about ``double free or corruption``. i googled for that; could it be that the pointer-swapping business makes glibc a bit dizzy so it becomes unable to correctly free memory? below i list first the ``setup.py`` that is needed to do the compilation (``/path/to/python3.1 ./setup.py build_ext --inplace``), then the edit distance code proper, so interested people find it easier to replicate. one more thing: this is run with Python3.1; one funny thing is that inside the ``*.pyx`` file we do have bare unicode strings, but ``print`` is still a statement, not a function. and yes i know this is a lot of code to paste here but the thing is the code is simply not runnable when you cut it down all too much. i believe all methods except ``editdistance()`` to work correctly, but feel free to point out any problems you perceive. ``setup.py``: from distutils.core import setup from distutils.extension import Extension from Cython.Distutils import build_ext setup( name = 'cython_dameraulevenshtein', ext_modules = [ Extension( 'cython_dameraulevenshtein', [ 'cython_dameraulevenshtein.pyx', ] ), ], cmdclass = { 'build_ext': build_ext }, ) ``cython_dameraulevenshtein.pyx`` (scroll all the way to the end to see the interesting stuff): ############################################################################################################ cdef extern from "stdlib.h": ctypedef unsigned int size_t void *malloc(size_t size) void *realloc( void *ptr, size_t size ) void free(void *ptr) #----------------------------------------------------------------------------------------------------------- cdef inline unsigned int _minimum_of_two_uints( unsigned int a, unsigned int b ): if a < b: return a return b #----------------------------------------------------------------------------------------------------------- cdef inline unsigned int _minimum_of_three_uints( unsigned int a, unsigned int b, unsigned int c ): if a < b: if c < a: return c return a if c < b: return c return b #----------------------------------------------------------------------------------------------------------- cdef inline int _warp( unsigned int limit, int value ): return value if value >= 0 else limit + value ############################################################################################################ # ARRAYS THAT SAY SIZE ;-) #----------------------------------------------------------------------------------------------------------- cdef class Array_of_unsigned_int: cdef unsigned int *data cdef unsigned int length #--------------------------------------------------------------------------------------------------------- def __cinit__( self, unsigned int length, fill_value = None ): self.length = length self.data = malloc( length * sizeof( unsigned int ) ) ###OBS### must check malloc doesn't return NULL pointer if fill_value is not None: self.fill( fill_value ) #--------------------------------------------------------------------------------------------------------- cdef fill( self, unsigned int value ): cdef unsigned int idx cdef unsigned int *d = self.data for idx from 0 <= idx < self.length: d[ idx ] = value #--------------------------------------------------------------------------------------------------------- cdef resize( self, unsigned int length ): self.data = realloc( self.data, length * sizeof( unsigned int ) ) ###OBS### must check realloc doesn't return NULL pointer self.length = length #--------------------------------------------------------------------------------------------------------- def free( self ): """Always remember the milk: Free up memory.""" free( self.data ) ###OBS### should free memory here #--------------------------------------------------------------------------------------------------------- def as_list( self ): """Return the array as a Python list.""" R = [] cdef unsigned int idx cdef unsigned int *d = self.data for idx from 0 <= idx < self.length: R.append( d[ idx ] ) return R ############################################################################################################ # CONVERTING UNICODE TO CHARACTER IDs (CIDs) #--------------------------------------------------------------------------------------------------------- cdef unsigned int _UMX_surrogate_lower_bound = 0x10000 cdef unsigned int _UMX_surrogate_upper_bound = 0x10ffff cdef unsigned int _UMX_surrogate_hi_lower_bound = 0xd800 cdef unsigned int _UMX_surrogate_hi_upper_bound = 0xdbff cdef unsigned int _UMX_surrogate_lo_lower_bound = 0xdc00 cdef unsigned int _UMX_surrogate_lo_upper_bound = 0xdfff cdef unsigned int _UMX_surrogate_foobar_factor = 0x400 #--------------------------------------------------------------------------------------------------------- cdef Array_of_unsigned_int _cids_from_text( text ): """Givn a ``text`` either as a Unicode string or as a ``bytes`` or ``bytearray``, return an instance of ``Array_of_unsigned_int`` that enumerates either the Unicode codepoints of each character or the value of each byte. Surrogate pairs will be condensed into single values, so on narrow Python builds the length of the array returned may be less than ``len( text )``.""" #......................................................................................................... # Make sure ``text`` is either a Unicode string (``str``) or a ``bytes``-like thing: is_bytes = isinstance( text, ( bytes, bytearray, ) ) assert is_bytes or isinstance( text, str ), '#121' #......................................................................................................... # Whether it is a ``str`` or a ``bytes``, we know the result can only have at most as many elements as # there are characters in ``text``, so we can already reserve that much space (in the case of a Unicode # text, there may be fewer CIDs if there happen to be surrogate characters): cdef unsigned int length = len( text ) cdef Array_of_unsigned_int R = Array_of_unsigned_int( length ) #......................................................................................................... # If ``text`` is empty, we can return an empty array right away: if length == 0: return R #......................................................................................................... # Otherwise, prepare to copy data: cdef unsigned int idx = 0 #......................................................................................................... # If ``text`` is a ``bytes``-like thing, use simplified processing; we just have to copy over all byte # values and are done: if is_bytes: for idx from 0 <= idx < length: R.data[ idx ] = text[ idx ] return R #......................................................................................................... cdef unsigned int cid = 0 cdef bool is_surrogate = False cdef unsigned int hi = 0 cdef unsigned int lo = 0 cdef unsigned int chr_count = 0 #......................................................................................................... # Iterate over all indexes in text: for idx from 0 <= idx < length: #....................................................................................................... # If we met with a surrogate CID in the last cycle, then that was a high surrogate CID, and the # corresponding low CID is on the current position. Having both, we can compute the intended CID # and reset the flag: if is_surrogate: lo = ord( text[ idx ] ) # IIRC, this formula was documented in Unicode 3: cid = ( ( hi - _UMX_surrogate_hi_lower_bound ) * _UMX_surrogate_foobar_factor + ( lo - _UMX_surrogate_lo_lower_bound ) + _UMX_surrogate_lower_bound ) is_surrogate = False #....................................................................................................... else: # Otherwise, we retrieve the CID from the current position: cid = ord( text[ idx ] ) #..................................................................................................... if _UMX_surrogate_hi_lower_bound <= cid <= _UMX_surrogate_hi_upper_bound: # If this CID is a high surrogate CID, set ``hi`` to this value and set a flag so we'll come back # in the next cycle: hi = cid is_surrogate = True continue #....................................................................................................... R.data[ chr_count ] = cid chr_count += 1 #......................................................................................................... # Surrogate CIDs take up two characters but end up as a single resultant CID, so the return value may # have fewer elements than the naive string length indicated; in this case, we want to free some memory # and correct array length data: if chr_count != length: R.resize( chr_count ) #......................................................................................................... return R #--------------------------------------------------------------------------------------------------------- def cids_from_text( text ): cdef Array_of_unsigned_int c_R =_cids_from_text( text ) R = c_R.as_list() c_R.free() ###OBS### should free memory here return R ############################################################################################################ # SECOND-ORDER SIMILARITY #----------------------------------------------------------------------------------------------------------- cpdef float similarity( char *a, char *b ): """Given two byte strings ``a`` and ``b``, return their Damerau-Levenshtein similarity as a float between 0.0 and 1.1. Similarity is computed as ``1 - relative_editdistance( a, b )``, so a result of ``1.0`` indicates identity, while ``0.0`` indicates complete dissimilarity.""" return 1.0 - relative_editdistance( a, b ) #----------------------------------------------------------------------------------------------------------- cpdef float relative_editdistance( char *a, char *b ): """Given two byte strings ``a`` and ``b``, return their relative Damerau-Levenshtein distance. The return value is a float between 0.0 and 1.0; it is calculated as the absolute edit distance, divided by the length of the longer string. Therefore, ``0.0`` indicates identity, while ``1.0`` indicates complete dissimilarity.""" cdef int length = max( len( a ), len( b ) ) if length == 0: return 0.0 return editdistance( a, b ) / length ############################################################################################################ # EDIT DISTANCE #----------------------------------------------------------------------------------------------------------- cpdef unsigned int editdistance( text_a, text_b ): """Given texts as Unicode strings or ``bytes`` / ``bytearray`` objects, return their absolute Damerau-Levenshtein distance. Each deletion, insertion, substitution, and transposition is counted as one difference, so the edit distance between ``abc`` and ``ab``, ``abcx``, ``abx``, ``acb``, respectively, is ``1``.""" #......................................................................................................... # This should be fast in Python, as it can (and probably is) implemented by doing an identity check in # the case of ``bytes`` and ``str`` objects: if text_a == text_b: return 0 #......................................................................................................... # Convert Unicode text to C array of unsigned integers: cdef Array_of_unsigned_int a = _cids_from_text( text_a ) cdef Array_of_unsigned_int b = _cids_from_text( text_b ) R = c_editdistance( a, b ) #......................................................................................................... # Always remember the milk: a.free() b.free() #......................................................................................................... return R #----------------------------------------------------------------------------------------------------------- cdef unsigned int c_editdistance( Array_of_unsigned_int cids_a, Array_of_unsigned_int cids_b ): # Conceptually, this is based on a len(a) + 1 * len(b) + 1 matrix. # However, only the current and two previous rows are needed at once, # so we only store those. #......................................................................................................... # This shortcut is pretty useless if comparison is not very fast; therefore, it is done in the function # that deals with the Python objects, q.v. # if cids_a.equals( cids_b ): return 0 #......................................................................................................... cdef unsigned int a_length = cids_a.length cdef unsigned int b_length = cids_b.length #......................................................................................................... # Another shortcut: if one of the texts is empty, then the edit distance is trivially the length of the # other text. This also works for two empty texts, but those have already been taken care of by the # previous shortcut: #......................................................................................................... if a_length == 0: return b_length if b_length == 0: return a_length #......................................................................................................... cdef unsigned int row_length = b_length + 1 cdef unsigned int row_length_1 = row_length - 1 cdef unsigned int row_bytecount = sizeof( unsigned int ) * row_length cdef unsigned int *oneago = malloc( row_bytecount ) ###OBS### must check malloc doesn't return NULL pointer cdef unsigned int *twoago = malloc( row_bytecount ) ###OBS### must check malloc doesn't return NULL pointer cdef unsigned int *thisrow = malloc( row_bytecount ) ###OBS### must check malloc doesn't return NULL pointer cdef unsigned int idx = 0 cdef unsigned int idx_a = 0 cdef unsigned int idx_b = 0 cdef int idx_a_1_text = 0 cdef int idx_b_1_row = 0 cdef int idx_b_2_row = 0 cdef int idx_b_1_text = 0 cdef unsigned int deletion_cost = 0 cdef unsigned int addition_cost = 0 cdef unsigned int substitution_cost = 0 #......................................................................................................... # Equivalent of ``thisrow = list( range( 1, b_length + 1 ) ) + [ 0 ]``: #print( '#305', cids_a.as_list(), cids_b.as_list(), a_length, b_length, row_length, row_length_1 ) for idx from 1 <= idx < row_length: thisrow[ idx - 1 ] = idx thisrow[ row_length - 1 ] = 0 #......................................................................................................... for idx_a from 0 <= idx_a < a_length: idx_a_1_text = _warp( a_length, idx_a - 1 ) twoago, oneago = oneago, thisrow #....................................................................................................... # Equivalent of ``thisrow = [ 0 ] * b_length + [ idx_a + 1 ]``: for idx from 0 <= idx < row_length_1: thisrow[ idx ] = 0 thisrow[ row_length - 1 ] = idx_a + 1 #....................................................................................................... # some diagnostic output: x = [] for idx from 0 <= idx < row_length: x.append( thisrow[ idx ] ) print print '#ED A', x #....................................................................................................... for idx_b from 0 <= idx_b < b_length: #..................................................................................................... idx_b_1_row = _warp( row_length, idx_b - 1 ) idx_b_1_text = _warp( b_length, idx_b - 1 ) #..................................................................................................... assert 0 <= idx_b_1_row < row_length, ( '#323', idx_b_1_row, ) assert 0 <= idx_a_1_text < a_length, ( '#324', idx_a_1_text, ) assert 0 <= idx_b_1_text < b_length, ( '#325', idx_b_1_text, ) #..................................................................................................... deletion_cost = oneago[ idx_b ] + 1 addition_cost = thisrow[ idx_b_1_row ] + 1 substitution_cost = oneago[ idx_b_1_row ] + ( 1 if cids_a.data[ idx_a ] != cids_b.data[ idx_b ] else 0 ) thisrow[ idx_b ] = _minimum_of_three_uints( deletion_cost, addition_cost, substitution_cost ) #..................................................................................................... # Transpositions: if ( idx_a > 0 and idx_b > 0 and cids_a.data[ idx_a ] == cids_b.data[ idx_b_1_text ] and cids_a.data[ idx_a_1_text ] == cids_b.data[ idx_b ] and cids_a.data[ idx_a ] != cids_b.data[ idx_b ] ): #................................................................................................... idx_b_2_row = _warp( row_length, idx_b - 2 ) assert 0 <= idx_b_2_row < row_length, ( '#340', idx_b_2_row, ) thisrow[ idx_b ] = _minimum_of_two_uints( thisrow[ idx_b ], twoago[ idx_b_2_row ] + 1 ) #..................................................................................................... # some diagnostic output: x = [] for idx from 0 <= idx < row_length: x.append( thisrow[ idx ] ) print '#ED B', x #......................................................................................................... # Here, ``b_length - 1`` can't become negative, since we already tested for ``b_length == 0`` in the # shortcut above: cdef unsigned int R = thisrow[ b_length - 1 ] #......................................................................................................... # Always remember the milk: # BUG: Activating below lines leads to glibc failing with ``double free or corruption`` #free( twoago ) #free( oneago ) #free( thisrow )e #......................................................................................................... return R #----------------------------------------------------------------------------------------------------------- def editdistance_reference( text_a, text_b ): """This method is believed to compute a correct Damerau-Levenshtein edit distance, with deletions, insertions, substitutions, and transpositions. Do not touch it; it is here to validate results returned from the above method. Code adapted from http://mwh.geek.nz/2009/04/26/python-damerau-levenshtein-distance""" # Conceptually, the implementation is based on a ``( len( seq1 ) + 1 ) * ( len( seq2 ) + 1 )`` matrix. # However, only the current and two previous rows are needed at once, so we only store those. Python # lists wrap around for negative indices, so we put the leftmost column at the *end* of the list. This # matches with the zero-indexed strings and saves extra calculation. b_length = len( text_b ) oneago = None thisrow = list( range( 1, b_length + 1 ) ) + [ 0 ] for idx_a in range( len( text_a ) ): twoago, oneago, thisrow = oneago, thisrow, [ 0 ] * b_length + [ idx_a + 1 ] #....................................................................................................... # some diagnostic output: print print '#EDR A', thisrow #....................................................................................................... for idx_b in range( b_length ): deletion_cost = oneago[ idx_b ] + 1 addition_cost = thisrow[ idx_b - 1 ] + 1 substitution_cost = oneago[ idx_b - 1 ] + ( text_a[ idx_a ] != text_b[ idx_b ] ) thisrow[ idx_b ] = min( deletion_cost, addition_cost, substitution_cost ) if ( idx_a > 0 and idx_b > 0 and text_a[ idx_a ] == text_b[ idx_b - 1 ] and text_a[ idx_a - 1 ] == text_b[ idx_b ] and text_a[ idx_a ] != text_b[ idx_b ] ): thisrow[ idx_b ] = min( thisrow[ idx_b ], twoago[ idx_b - 2 ] + 1 ) #..................................................................................................... # some diagnostic output: print '#EDR B', thisrow #..................................................................................................... return thisrow[ len( text_b ) - 1 ]