
Untitled
By: a guest on
Jul 29th, 2012 | syntax:
None | size: 1.15 KB | hits: 13 | expires: Never
fork() in for() loop
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/wait.h>
int main(int argc, char *argv[]){
int limit = argc/2;
if(argc%2 == 0){
perror("the number of arguments given must pe even!");
exit(1);
}
int i;
for(i=0; i<=limit; i++){
if(fork()==-1){
perror("childes couldn't be createdn");
exit(1);
}
if(fork()==0){
printf("fork: %d n",i);
exit(1);
}
wait(0);
}
printf("exiting...n");
return 0;
}
warzaru@ubuntu:~/OS/UprocH$ ./exe a b c d
fork: 0
fork: 0
fork: 1
fork: 1
fork: 1
fork: 2
fork: 2
fork: 1
fork: 2
exiting...
exiting...
fork: 2
exiting...
exiting...
fork: 2
exiting...
exiting...
exiting...
warzaru@ubuntu:~/OS/UprocH$ fork: 2
fork: 2
fork: 2
exiting...
if(fork()==-1){} // first fork
if(fork()==0){} // second fork
pid = fork();
if(pid == -1)
{
... //failed
}
else if(pid == 0)
{
... //success
}
switch(fork())
{
case -1:
... // failed
break;
case 0:
... // success
break;
}