// The C equivalent of my application

#include <stdio.h>

int main()
{
    int i = 0;
    int p = 0;

    float test;

    while(i<5000000)
    {
        if(p == 100000)
        {
            printf("%d\n",i);
            p = 0;
        }

        // The meat of the application
        test = (3 * 4.5) / 12 + (34 * 78.999) / 12.3444;
        test = (3 * 4.5) / 12 + (34 * 78.999) / 12.3444;
        test = (3 * 4.5) / 12 + (34 * 78.999) / 12.3444;

        i = i + 1;
        p = p + 1;
    }

    return 0;
}