4.)	You catch Gilligan sabotaging another attempt to get off the island. You can’t figure out why they let him walk around. When you try to stop him, he gets spooked and trips, causing him to slide down a frictionless hill. His slide starts at 7.1 m above sea level, with an initial speed of zero. Gilligan has a mass of 63 kg.

a.	The hill ends in a cliff 2.8 m above sea level. Using energy arguments, find how fast Gilligan is moving when he reaches the cliff?
a. p=63*9.81*7.1+0
b. e=63*9.81*2.8+(1/2)63*v^2
4388.01 = 1730.48+31.5v^2
2657.52 = 31.5v^2
84.365 = v^2
v=9.81 m/s
b.	At the edge of the cliff, a vine hangs vertically from a branch 5 m above the edge. Gilligan grabs hold just in time, and swings. During the swing, air drag does 872.4 J of work. How high above sea level is Gilligan when his swing stops?
63*9.81*5+k-872.4 = 63*9.81*h
63*9.81*5-872.4 = 63*9.81*h
2217.75 = 618.03h
h = 3.58 m
c.	What angle does is the vine make from the vertical at the point where the swing stops?
Triangle: c is the length of the vine.
the leg is the distance above ground.
the base is the distance x which he has moved.

d.	At the point where the swing stops, the vine breaks, and Gilligan falls. Fortunately, the Skipper has set up a spring directly under Gilligan. The rest position of the spring is 1 m above sea level, and the spring has a spring constant of k = 10,000 N/m. Gilligan lands on the spring, saving his life so he can go on preventing the group’s rescue. How fast is Gilligan moving when he hits the spring? How high is Gilligan above sea level when the spring is fully compressed?