If we list all the natural numbers <= 20 that are multiples of 3 xor 5, we get:

    3, 5, 6, 9, 10, 12, 18, 20

Note, 15 is not included because multiples of both 3 and 5 are excluded from the above series.

In a language of your choice, write a program that takes a positive integer 'N' as an argument and prints all multiples of 3 xor 5 up to (and including) N.



import itertools

def  printmultiple (n):
    if n.isdigit():
        flag_3 = None
        flag_5 = None

    if (n%3 == 0):
        flag_3 = True
    if (n%5 == 0):
        flag_5 = True
    if ( flag_3 == True or flag_5 == True):
        yield n

newlist = []
arr = range(0,21)
for i in arr:
     newlist.append(printmultiple(i))

print newlist