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'''
Python 3.x solution to puzzle at:
http://programmingpraxis.com/2009/06/16/who-owns-the-zebra/
'''

import itertools

colors = ('yellow', 'blue', 'red', 'ivory', 'green')
nationalities = ('Norwegian', 'Ukranian', 'Englishman', 'Spaniard', 'Japanese')
drinks = ('water', 'tea', 'milk', 'orange juice', 'coffee')
brands = ('Kools', 'Chesterfields', 'Old Gold', 'Lucky Strikes', 'Parliaments')
pets = ('fox', 'horse', 'snails', 'dog', 'zebra')

count = 0  # Count of solutions, just in case there is more than one.

for n in itertools.permutations(nationalities):
    if n.index('Norwegian') != 0:
        continue
    for d in itertools.permutations(drinks):
        if (d.index('milk') != 2 or
            n.index('Ukranian') != d.index('tea')):
            continue
        for c in itertools.permutations(colors):
            if (n.index('Englishman') != c.index('red') or
                d.index('coffee') != c.index('green') or
                c.index('green') != (c.index('ivory') + 1) or
                abs(n.index('Norwegian') - c.index('blue')) != 1):
                continue
            for b in itertools.permutations(brands):
                if (b.index('Kools') != c.index('yellow') or
                    b.index('Lucky Strikes') != d.index('orange juice') or
                    n.index('Japanese') != b.index('Parliaments')):
                    continue
                for p in itertools.permutations(pets):
                    if (n.index('Spaniard') != p.index('dog') or
                        b.index('Old Gold') != p.index('snails') or
                        abs(b.index('Chesterfields') - p.index('fox')) != 1 or
                        abs(b.index('Kools') - p.index('horse')) != 1):
                        continue
                    count +=1
                    print('Solution #', count, ':', sep = '')
                    print('Water drinker: ', n[d.index('water')])
                    print('Zebra owner: ', n[p.index('zebra')])
# End of script.

1	-
1	+	'''
2		Python 3.x solution to puzzle at:
3		http://programmingpraxis.com/2009/06/16/who-owns-the-zebra/
4		'''
5
6		import itertools
7
8		colors = ('yellow', 'blue', 'red', 'ivory', 'green')
9		nationalities = ('Norwegian', 'Ukranian', 'Englishman', 'Spaniard', 'Japanese')
10		drinks = ('water', 'tea', 'milk', 'orange juice', 'coffee')
11		brands = ('Kools', 'Chesterfields', 'Old Gold', 'Lucky Strikes', 'Parliaments')
12		pets = ('fox', 'horse', 'snails', 'dog', 'zebra')
13
14		count = 0 # Count of solutions, just in case there is more than one.
15
16		for n in itertools.permutations(nationalities):
17		if n.index('Norwegian') != 0:
18		continue
19		for d in itertools.permutations(drinks):
20		if (d.index('milk') != 2 or
21		n.index('Ukranian') != d.index('tea')):
22		continue
23		for c in itertools.permutations(colors):
24		if (n.index('Englishman') != c.index('red') or
25		d.index('coffee') != c.index('green') or
26		c.index('green') != (c.index('ivory') + 1) or
27		abs(n.index('Norwegian') - c.index('blue')) != 1):
28		continue
29		for b in itertools.permutations(brands):
30		if (b.index('Kools') != c.index('yellow') or
31		b.index('Lucky Strikes') != d.index('orange juice') or
32		n.index('Japanese') != b.index('Parliaments')):
33		continue
34		for p in itertools.permutations(pets):
35		if (n.index('Spaniard') != p.index('dog') or
36		b.index('Old Gold') != p.index('snails') or
37		abs(b.index('Chesterfields') - p.index('fox')) != 1 or
38		abs(b.index('Kools') - p.index('horse')) != 1):
39		continue
40		count +=1
41		print('Solution #', count, ':', sep = '')
42		print('Water drinker: ', n[d.index('water')])
43		print('Zebra owner: ', n[p.index('zebra')])
44		# End of script.