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- 1.
- _____
- z^n = |z|^ncis(n0)
- 2.
- _____
- z1 = a+bi
- z2 = c+di
- z1+z2 = (a+c)+(b+d)i
- z1-z2 = (a-c)+(b-d)i
- z1*z2 = ac + adi + bci - bd
- z1/z2 = (a+bi)*(c-di)/
- (c+di)*(c-di)
- _____
- 3.
- _____
- z1 = |z1|cis0
- z2 = |z2|cis0
- z1*z2 = (|z1|z2|)cis(0+0)
- z1/z2 = (|z1/z2|)cis(0-0)
- 4.
- _____
- sin^20+cos^20 = 1
- tan^20+1 = sec^20
- cot^20+1 = cosec^20
- 5.
- _____
- tan-1(√3)) =π/3
- tan-1(1/√3)=π/6
- tan-1(1) =π/4
- 6.
- ____
- sin(a+-b)=sin(a)cos(b)+- cos(a)sin(b)
- cos(a+-b)=cos(a)cos(b)-+ sin(a)sin(b)
- tan(a+-b)=tan(a)+-tan(b)/
- 1 -+ tan(a)tan(b)
- 7.
- ____
- sec(x)=1/cos(x)
- csc(x)=1/sin(x)
- cot(x)=1/tan(x)=Cos/Sin
- tan(x)=1/cot(x)=Sin/Cos
- 8.
- ____
- (cos0+sin0)^n -> use fibonachi
- for proofs
- n = 2, 121
- 3, 1331
- 4, 14641
- 9.
- ____
- z^n=x
- z^n=xcisπ
- z^n=xcisπ+2kπ
- z =(xcisπ+2kπ)^1/n
- -->
- z = xcis1/n(π+fkπ/m)
- z = xcisπ/nm(1+fk)
- 10.
- ____
- Express asinx+bcosx in form
- Asin(x+0)
- Acos0sinx+Asin0cosx = asinx+-bcosx
- rearange
- Acos0 = a, Asin0 = b.
- A^2 = A^2 + 1
- A^2 = A^2(cos^20+sin^20)
- = √a^2+b^2
- tan0 = Asin0/Acos0
- 0 = tan-1(b/a)
- asinx+bcosx =
- A sin (x + tan-1(b/a))
- A cos (x + tan-1(-a/b))
- asinx-bcosx =
- A sin (x + tan-1(-b/a))
- A cos (x + tan-1(a/b))
- Sketch asin(x+c)
- a = amp, ps = -c.
- 1.
- ____
- Transformation
- (a c)(x) where x,y is
- (b d)(y) vector
- where a,b is x Line
- where c,d is y Line
- 2.
- ____
- Finding Multiple
- (T3)(T2)(T1)(V)
- (T3)->(T2)->(T1)
- (T123) is Tm
- 3.
- ____
- Identity
- (1 0)
- (0 1)
- ReflectionX(Mx)
- (1 0)
- (0 -1)
- ReflectionY(My)
- (-1 0)
- ( 0 1)
- ReflectionY=x(My=x)
- (0 1)
- (1 0)
- Dilation(Enlargment)=x(Dk)
- (k 0)
- (0 k)
- Rotation(R0)
- (cos0 -sin0)
- (sin0 cos0)
- 4.
- ____
- Translations
- Xi + Yj
- 5.
- ____
- When transformation is (a,b)
- y=x
- sub vector
- -> (y+b) = (x+a)
- -> let transformation be (a,b)
- if solving..
- 6.
- ____
- When transformations are like
- Ti = ai+bj
- Tj = ci+dj
- Tm = (a c)
- (b d)
- 7.
- ____
- When transfomation is Matrix
- (x') (a b)(x)
- (y')=(c d)(y)
- where x,y is vec,
- x'y' is image.
- x'= ax+by and
- y'= cx+dy
- (x')(a b)-1 (x)
- (y')(c d) =(y)
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