for demo

bash-4.2$ a=(user1 pass1 user2 ls\;ls user3 pass#3)

bash-4.2$ for ((i=0;i<${#a[@]};i+=2)); do echo "User ${a[i]}"; echo "Password ${a[i+1]}"; done
User user1
Password pass1
User user2
Password ls;ls
User user3
Password pass#3