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May 22nd, 2015
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  1. %F
  2. %druge vrstice vektorja F
  3. %VPf2 = x(1)^2 + cos(x(2))*x(3)^2 -1; %primer 1
  4. %VPf2 = x(2)^4 + log(x(1)^2+1)*x(2)^2 - 4; %primer 2
  5. VPf2 = x(2)^4 + log(x(1)^2+1)*x(3)^2 - 4; %primer 3
  6. %VPf2 = -x(1)^2 + cos(x(2))*sin(x(3)) +0.5; %primer 4
  7. %VPf2 = x(1)^2 + x(2)^2 + x(3)^2 + sin(3*x(1)) + sin(3*x(2)) + sin(3*x(3)) - 1; %primer 8
  8.  
  9. % JF --> elementi druge vrstice JF, prva je itak zmer ista
  10. %primer 1
  11. VPf2dx = 2*x(1);
  12. VPf2dy = -x(3)^2 * sin(x(2));
  13. VPf2dz = cos(x(2))*2*x(3);
  14.  
  15. %primer2:
  16. %VPf2dx = (2* x(1) * x(3)^2)/(x(1)^2 +1);
  17. %VPf2dy = 4*x(2)^3;
  18. %VPf2dz = 2*x(3)*log(x(1)^2+1);
  19.  
  20. %primer3
  21. VPf2dx =(2*x(1)*x(3)^2) / (x(1)^2 + 1);
  22. VPf2dy =4*x(3)^3;
  23. VPf2dz =2*x(3)*log(x(1)^2+1);
  24.  
  25. %primer4
  26. %VPf2dx = -2*x(1);
  27. %VPf2dy = -sin(x(2))*sin(x(3));
  28. %VPf2dz = cos(x(2))*cos(x(3));
  29.  
  30. %primer8:
  31. %VPf2dx = 2*x(1) + 3*cos(3*x(1));
  32. %VPf2dy = 2*x(2) + 3*cos(3*x(2));
  33. %VPf2dz = 2*x(3) + 3*cos(3*x(3));
  34. Jac = [VPf1dx VPf1dy VPf1dz;VPf2dx VPf2dy VPf2dz];
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